MohamedSalim malik

Hey friends ,
Can anyone tell me about this Java and C# debacle . The Answer i want to know is , that whether the Microsoft create C# out of java. Is C# a copy of Java ?. I want to know about this history for a assignment. i have Google about this matter already . But i couldn't find good information . so if anyone know about this , please be kind to share the links . thank you

Wow, I got it now. Thanks a lot Sebanti Sanyal for your Short and Sweet answer. You are awesome

Hey friends , i have this problem with Thread Synchronization. please look at the following class where i created two threads by implementing Runnable interface. in here i can only get the results ABAB, Because
I am using two different threads with two different runnable targets. Am i correct. I only want to know my theory is correct? please somebody tell me.


class TestA implements Runnable { synchronized public void run() { System.out.println("A"); System.out.println("B"); } public static void main(String args[]) { new Thread(new TestA()).start(); new Thread(new TestA()).start(); } }


and The second class , I can get two results as "ABAB" , and "AABB" . am i right? It is because i am using the same runnable target for different Threads . Is my theory correct. or please somebody tell me if the way i understand is wrong. and please forgive my bad use of English.

class TestB implements Runnable { synchronized public void run() { System.out.println("A"); System.out.println("B"); } public static void main(String args[]) { TestB b = new TestB(); new Thread(b).start(); new Thread(b).start(); } }

There were no reassignment happened. C variable only got assigned inside the constructor. You have to initialize the final variable before constructor finished. please correct me if i am wrong. forgive my bad English .

Thanks alot Walter.. sorry for this delay to reply. your solution did work .

My problem is , i can access( or print) that s variable from inside the method; but i cannot access( or print ) it from the class itself. when i try to do like that(uncommenting the line) it gives me a compilation error. why is that?
As i know, a method local inner class can access any instance variable from the outer class. but here i get a compilation error. thank you

Guys, I am Studying for OCJP exam. i got this problem today . Anyone please give me an answer for this

public class MyJava { private String s = "Malik" ; public void eat(){ class Test { // System.out.println(s); public void ABC(){ System.out.println(s); } } } }

As you can see in this above code , i can print the variable 's' inside the method that is located inside the method local inner class. but why i cant print the same variable inside method local inner class itself(i commented out that line). it gives me a compilation error. anyone kind enough to explain me.

Awesome artical.. now i got it.. thanks for your help.. :

class test3{ public static void main(String args[]){ String s1="ABC"; String s2="ABC"; System.out.println(s1==s2); } }
In my SCJP class they taught us like Strings are considered as Objects in java.. If so the above s1,s2 should be two references which points to TWO OBJECTS . Am i correct.?
But when i compile and run this i got a result showing true. I am confused


then i made another program..

class test4{ public static void main(String args[]){ String s3=new String("XYZ"); String s4=new String("XYZ"); System.out.println(s3==s4); } }


When i run this, it showed the boolean value as 'false'. It indicates that this is two different objects.(is that correct?) My question is that, which is considered as
a OBJECT in java From above two declarations.?? can someone explain me?

Thank you Rob Spoor .. yeah that the point where i did the mistake. i didnt convert the string value to a double. then i corrected the source code, and it did work.. :

class E{
public static void main(String args[]){
double gpa=Double.parseDouble(args[0]);
if(gpa>=3.6)
{
System.out.println("First class");
}

else if(3.59>=gpa && gpa>=3.4)
{
System.out.println("Upper Second class");
}

else if(3.49>=gpa && gpa>=3.00)
{
System.out.println("Lower second class");
}

else if(2.99>=gpa && gpa>=2.00)
{
System.out.println("Pass");
}
else
{
System.out.println("Fail");
}
}
}

Yeah thank you for advice. : I tried to pass the argument to the variable using command line. i tried in various ways . but still this error occurs.. This is the error message occured when i try to compile the program.
E.java:3: ';' expected
double gpa(args[0]);
^
E.java:3: not a statement
double gpa(args[0]);
^
E.java:3: ';' expected
double gpa(args[0]);
^
3 errors

I try to build this if-else by passing a command line arguament to the variable gpa.but i get an error. can someone help me please with this problem. thank you

class E{ public static void main(String args[]){ double gpa(args[0]); if(gpa>=3.6) { System.out.println("First class"); } else if(3.59>=gpa && gpa>=3.4) { System.out.println("Upper Second class"); } else if(3.49>=gpa && gpa>=3.00) { System.out.println("Lower second class"); } else if(2.99>=gpa && gpa>=2.00) { System.out.println("Pass"); } else { System.out.println("Fail"); } } }

Thank you. :

What is really mean by pass by value and pass by reference. Is java using both methods. How can we identify these two methods. and what is the most appropriate method?
Can anyone help me please with a example.. thank you. :

Thank you Fred rosenberger .. Your method helped me alot.. : I followed those step by step method you have mentioned and i got the out put.. Thanks for sharing the idea.. :