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What is the result of this code?
A. It prints X and exits
B. It prints X and never exits
C. It prints XY and exits almost immeditately
D. It prints XY with a 10-second delay between X and Y
E. It prints XY with a 10000-second delay between X and Y
F. The code does not compile
G. An exception is thrown at runtime
Answer:
✓ G is correct.The code does not acquire a lock on t before calling t.wait(), so it throws an
IllegalMonitorStateException. The method is synchronized, but it's not synchronized
on t so the exception will be thrown. If the wait were placed inside a synchronized(t)
block, then the answer would have been D.
hi
i understand the answer
but let's (assume) that the code is correct and would compile
as you can see we didn't override the run() method....we used the one in the Thread class and it doesn't print anything
but when we did t.start() the run() method still ran even though nothing is printed....so after that isn't the thread t supposed to be dead??? i mean we did call t.wait() after that and i believe that the thread would be dead by that time???
so what do you think?
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