chrstian ferma

why not string .replace before parsing replace "," to "" and also replace "%" to "" then parse to type that you need double or int

//html <select> <option>Option 1</option> <option>Option 2</option> <option>Option 3</option> </select> //css select option { padding:10px 0px 0px 10px; }
the style didn't work on chrome but works on firefox any suggestions?
thank you

Richard Tookey wrote:This whole approach seems a bit cack-handed . I haven't used Javascript for some time so am rusty but the only thing you are using the regex for is to check for a valid character and even that is wrong. Why not just use str = str.replace(/[^0-9]/g, '');

Gets rid of 99% of your code!

thanks man this one is more easy to understand few lines of codes into one line than my previous thanks

Good day everyone i have a text field that i only allow numbers but when i drop a value or paste that is produced by shift + the numbers 0 to 10 = "!@#$%^&*()" then i try to drag and drop this or paste into the textbox where i bind into a regular expression it allow the special characters , i dont have any problem on this regular expression on keypress

$('#numbersOnlyTextBoxId').on('input propertychange',function(e){ //regular expression for numbers only "\b" is for backspace and "\t" is for the tab var numbersOnlyRegularExpression=new RegExp("^[0-9\b\t]+$"); //the value that was drop or paste var dragAndDropValueOrPaste = $(this).val(); //value size var dragAndDropValueOrPastesize = $(this).val().length; var value=""; //iteration depends on the size of drop or paste value for(i=0; i<dragAndDropValueOrPastesize;i++){ //i have this line below so that i can test every letter on string that i paste or drop var valuePerChar = dragAndDropValueOrPaste.charAt(i); //test each value if it match on the regular expression if(numbersOnlyRegularExpression.test(valuePerChar)){ value+=valuePerChar; } } //set all the valid value into textbox after the iteration $(this).val(value); }) //drop and paste //sample data: 1!1!1!1!1!1!1! //when i drag and drop it : 1!1!1!1!1!1!1! //expected : 1111111 //keypress no problem //sample data : 1!1!1!1!1!1 //after keypress : 111111 //expected : 111111

Good day every one here's the scenario in my drop down when i have error on drop down it will have a error class and a tooltip , but when i click the drop down to show the options i destroy the tooltip so the tool tip will not show when you click drop down but im having some hard time how to figure out putting back the tooltip when the drop down is already close or i click outside the drop down i already made some research i try to get the length but i think this is not applicable in this scenario cause in my drop down i have a default value w/c means that the length of it will always 1 thank you

//class error .error{ border:1px solid red; } //assume that i have error on my page so i will add a class error and also a tooltip function validate(){ $("#dropDownId").addClass("error"); $("#dropDownId").tooltip({ placement : "bottom" title : "drop down has error" }); } //check if i click on dropdown it will check first if it has a class error before removing the tooltip $(document).ready(function(){ $("#dropDownId").click(function(){ var checkIfHasError = $(this).hasClass("error"); //check if already has a class error if( checkIfHasError ){ console.log('destroy tooltip'); $('#fromTSId').tooltip("destroy"); } });

Got this ,
$(this).parents('tr').prev().find('input[type="text"]').val();
this solves the problem

I click the second textbox then i aiming to get the value of the prevoius textbox
<tr> <td><input type="text" name="textbox1" style="width: 100%" value="xxxxxx"></td> <td><input type="text" name="textbox1" style="width: 100%" ></td> <tr> $('input[name="textbox1"]').click(function(e){ //option 1 var tb = $(this).prev().val(); alert(tb); //it returns nothing a blank alert pop up //option 2 var tb = $(this).parent().find('input').val(); alert(tb); //it returns nothing a blank alert pop up //option 3 var tb = $(this).prevAll("input[type=text]").val(); alert(tb); //it returns nothing a blank alert pop up //option 4 var tb = $(this).parent('td').find('input[type="text"]').prev().val(); alert(tb); //it returns nothing a blank alert pop up //option 5 var tb = $(this).parents('tr').find('input[type="text"]').prev().val(); alert(tb); //it returns nothing a blank alert pop up //option 6 var tb = $(this).parents('tr').parent('td').find('input[type="text"]').prev().val(); alert(tb); //it returns nothing a blank alert pop up //option 7 var tb = $(this).closest('td').prev().val(); alert(tb); //it returns nothing a blank alert pop up var tb =$(this).prev().prev().val(); alert(tb); //it returns nothing a blank alert pop up //this one working but this is not what i amining var tb = $(this).val(); alert(tb); });


i already try those and i always get a blank alert pop up

Bear Bibeault wrote:The difference is subtle but distinct. The key press event is triggered only for keys that produce characters, whereas keydown is triggered for all keys.

You can see the difference by creating a test page that captures both events for an input. You will see that both events are triggered when a key such as Q is pressed. But what about when you press the SHIFT key? What happens differently?

yes i see the difference of keydown and key press thank you

Good day, im reading about keypress,key up and key down
key down = event will trigger after you press the key (more easy to understand based on definition and you can easily know how it works)
but im a bit confuse of key down and keypress i try to use them and it seems that they are the same based on functionality.
Just want to know more how key press and key down becomes different? thank you.

Winston Gutkowski wrote:

chrstian ferma wrote:cause i cant understant how the pattern generated...

Well I'm afraid that's an absolute must. All I've been doing is musing about possibilities.

If this is for a class, then I suggest you ask your tutor, because what you've given us is definitely not enough to go on.

Winston

thanks i believe i need more details regarding this

my bad not a detailed post , my post looks like im looking on exact answer

Winston Gutkowski wrote:

Joanne Neal wrote:* For example
How does that pattern relate to the value 9 ?

That's what I was trying to work out.

As far as I could see, each pattern is 9 characters long, and is made up of 6 '0's and 3 '*'s; but since 9 is the ONLY single-digit odd number that isn't prime, it doesn't seem to give much of a clue.

Winston

thank you what im looking is a guidance not the exact answer

chrstian ferma wrote:Write a program that will display a pattern depending on n. Assume n as a one digit odd number.



Example: if n=9, display
*000*000*
0*00*00*0
00*0*0*00
000***000

cause i cant understant how the pattern generated , i believe this one can easily done by for loop thank you , i appreciate the answers i believe n=9 then system.out the expected output is not what im trying to explain but it's a valid answer due to not detailed question

Write a program that will display a pattern depending on n. Assume n as a one digit odd number.

Example: if n=9, display
*000*000*
0*00*00*0
00*0*0*00
000***000