Eric Zanders

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since Sep 15, 2004
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Recent posts by Eric Zanders

Dear Pradip,
don't mean to be rude but according to my (Belgian) calendar that be September 21st..........
[ August 16, 2006: Message edited by: Eric Zanders ]
Thx Ramesh!
After taking a short look at the links (or at least at the pages they refer to ) I'm sure there is a future for AJAX.

I recently heared something buzzing about AJAX.
Can anybody please explain, in a nutshell, how I can implement or make use of it in my current and next developments? What are the real advantages (for the users as well as for me)?

Thx 4 D feedback.

Dear Seema,

does the examinator already cover JAVA 5?
As I am only active with JAVA for about a year now, would it take me long to get prepared with your examinator?

Thx for your reply.
Hi there,

I'm kind of new (less than 1 year taking courses and being 'productive') to OO and JAVA and what they call a (very) late starter: I'm nearing the 40's and thought that JAVA-programming would be a cool new turningpoint in my job curriculum...
As I'm so 'fresh' in the whole concept of OO and JAVA I was wondering if your book would be helpfull to fill-in the remaining blind spots?
Also there are people asking me if I can be persuaded to taking on JAVA-tests so that they see that their investments do pay up.
Would your book be a good guideline in, let's say, getting me through the JAVA(5)-exams?

Thanks for your reply.

17 years ago
Found it!!!

In a nutshell: you refer a1 to an A with value "A1" and an otherA with value "A2". Same goes for a2 (A2 & A3) and a3(A3 & A1).
In the for-loop you ask of a0 to refer to the otherA value of the A it is referring to, thus creating a loop. If you increase the maxvalue of i in the for-statement (ie to 9), you'll see A1A2A3A1A2A3A1A2A3A1A2A3, the last A1A2A3-cycle always being created by finalize() (due to the garbage collection).

Am I right? It may be that I still mix-up terminologies, for that I apologize. (This is only my 7� week of Java...)
[ October 27, 2004: Message edited by: Eric Zanders ]
Thanks Barry, it now results in answer d...
[ October 27, 2004: Message edited by: Eric Zanders ]
What I always try is to compile and see the result myself.
I then insert 'printing'messages to try and trace the path that is being followed. However, in this case after compiling succesfully and trying to run it, I got this errormessage:
Exception in thread "main" java.lang.NoSuchMethodError: main

Anyone got a clue?
being a beginner aswell, I'll try to explain how I get to 3 objects:

Originally posted by Fendel Coulptz:

then how many string objects are created in this example? i don't understand why 3 objects are created.

String s1,s2,s3,s4;
s1 = "Hello";
s2 = s1;
s3 = s2 + "Pal";
s4 = s3;

1� object is "Hello" which is referenced by s1 and s2.
2� object is "Pal"
and the 3� object is the concatenation of "Hello" (referenced by s2) and "Pal", thus resulting in "HelloPal" being referenced by s3 and s4.

About the a1==a2 case, I believe there is a typo in

String a2 = "alibaba and forty theives";

If I'm wrong, please do forgive AND correct me.

More @ this link The SCJP Tip Line
[ October 27, 2004: Message edited by: Eric Zanders ]
18 years ago

To convert an ASCII(int) to its corresponding char:

where i is an int with a value between 33 & 126 (resulting in an upper- or lowercase letter or a number)

The other way 'round:

where a is a char, being upper- or lowercase or a number.

Hoping to have been of any assistance.
18 years ago
The actual question is: who's dealin' and which cardgame is this anyway?
That's because you're missing a piece, Mani.
It works fine with me...
Thanks Paul.
So returning to the initial question, the result (number of String objects) then should be 6?
18 years ago
Dear Paul,

As I'm only a beginner I tend to make mistakes. (which is normal, I guess...)

Would it have been more correct if I had stated that the content of the object s1 was modified?

Anyway, thanks for correcting me. How else am I going to learn from my mistakes?


18 years ago

I would say 5:
1� s1.
2� s2.
3� The string concatenation is not stored in s1 but it exists.
4� Same case for the s2 string concatenation.
5� The string you'll print is the concatenation s1, a blank and s2.

To verify this I created a little testprogram:

When you run this, you'll notice that:
- s1 only gets concatenated with "winter " because of the statement
s1 += "winter "; which is written out in full s1 = s1 + "winter ";
thus resulting in modification of s1.
- s2 is never modified.


18 years ago